-3+2(4x-13)=-40x+78

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Solution for -3+2(4x-13)=-40x+78 equation: 



-3+2(4x-13)=-40x+78

We move all terms to the left:

-3+2(4x-13)-(-40x+78)=0

We multiply parentheses

8x-(-40x+78)-26-3=0

We get rid of parentheses

8x+40x-78-26-3=0

We add all the numbers together, and all the variables

48x-107=0

We move all terms containing x to the left, all other terms to the right

48x=107

x=107/48

x=2+11/48

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