-3(z+3)=2(2-z)

Solution for -3(z+3)=2(2-z) equation:

-3(z+3)=2(2-z)

We move all terms to the left:

-3(z+3)-(2(2-z))=0

We add all the numbers together, and all the variables

-3(z+3)-(2(-1z+2))=0

We multiply parentheses

-3z-(2(-1z+2))-9=0


We calculate terms in parentheses: -(2(-1z+2)), so:

2(-1z+2)

We multiply parentheses

-2z+4

Back to the equation:

-(-2z+4)


We get rid of parentheses

-3z+2z-4-9=0

We add all the numbers together, and all the variables

-1z-13=0

We move all terms containing z to the left, all other terms to the right

-z=13

z=13/-1

z=-13