-3(y-5)+4=6-(y-3)

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Solution for -3(y-5)+4=6-(y-3) equation: 



-3(y-5)+4=6-(y-3)

We move all terms to the left:

-3(y-5)+4-(6-(y-3))=0

We multiply parentheses

-3y-(6-(y-3))+15+4=0



We calculate terms in parentheses: -(6-(y-3)), so:

6-(y-3)

determiningTheFunctionDomain
-(y-3)+6

We get rid of parentheses

-y+3+6

We add all the numbers together, and all the variables

-1y+9

Back to the equation:

-(-1y+9)



We add all the numbers together, and all the variables

-3y-(-1y+9)+19=0

We get rid of parentheses

-3y+1y-9+19=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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