-3(y-3y)+3=-6(3y-y)+5+17y

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Solution for -3(y-3y)+3=-6(3y-y)+5+17y equation: 



-3(y-3y)+3=-6(3y-y)+5+17y

We move all terms to the left:

-3(y-3y)+3-(-6(3y-y)+5+17y)=0

We add all the numbers together, and all the variables

-3(-2y)-(-6(+2y)+5+17y)+3=0

We multiply parentheses

6y-(-6(+2y)+5+17y)+3=0



We calculate terms in parentheses: -(-6(+2y)+5+17y), so:

-6(+2y)+5+17y

determiningTheFunctionDomain
-6(+2y)+17y+5

We add all the numbers together, and all the variables

17y-6(+2y)+5

We multiply parentheses

17y-12y+5

We add all the numbers together, and all the variables

5y+5

Back to the equation:

-(5y+5)



We get rid of parentheses

6y-5y-5+3=0

We add all the numbers together, and all the variables

y-2=0

We move all terms containing y to the left, all other terms to the right

y=2

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