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-3(y+3)=3y-9+2(5y+4)
We move all terms to the left:
-3(y+3)-(3y-9+2(5y+4))=0
We multiply parentheses
-3y-(3y-9+2(5y+4))-9=0
We calculate terms in parentheses: -(3y-9+2(5y+4)), so:We get rid of parentheses
3y-9+2(5y+4)
determiningTheFunctionDomain 3y+2(5y+4)-9
We multiply parentheses
3y+10y+8-9
We add all the numbers together, and all the variables
13y-1
Back to the equation:
-(13y-1)
-3y-13y+1-9=0
We add all the numbers together, and all the variables
-16y-8=0
We move all terms containing y to the left, all other terms to the right
-16y=8
y=8/-16
y=-1/2
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