-3(y+1)=5y-3+3(2y+4)

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Solution for -3(y+1)=5y-3+3(2y+4) equation:



-3(y+1)=5y-3+3(2y+4)
We move all terms to the left:
-3(y+1)-(5y-3+3(2y+4))=0
We multiply parentheses
-3y-(5y-3+3(2y+4))-3=0
We calculate terms in parentheses: -(5y-3+3(2y+4)), so:
5y-3+3(2y+4)
determiningTheFunctionDomain 5y+3(2y+4)-3
We multiply parentheses
5y+6y+12-3
We add all the numbers together, and all the variables
11y+9
Back to the equation:
-(11y+9)
We get rid of parentheses
-3y-11y-9-3=0
We add all the numbers together, and all the variables
-14y-12=0
We move all terms containing y to the left, all other terms to the right
-14y=12
y=12/-14
y=-6/7

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