-3(y+1)+7y=(4y+1)-5

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Solution for -3(y+1)+7y=(4y+1)-5 equation: 



-3(y+1)+7y=(4y+1)-5

We move all terms to the left:

-3(y+1)+7y-((4y+1)-5)=0

We add all the numbers together, and all the variables

7y-3(y+1)-((4y+1)-5)=0

We multiply parentheses

7y-3y-((4y+1)-5)-3=0



We calculate terms in parentheses: -((4y+1)-5), so:

(4y+1)-5

We get rid of parentheses

4y+1-5

We add all the numbers together, and all the variables

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

4y-(4y-4)-3=0

We get rid of parentheses

4y-4y+4-3=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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