-3(x-8)=4(-6+1/4x)

Solution for -3(x-8)=4(-6+1/4x) equation:

-3(x-8)=4(-6+1/4x)

We move all terms to the left:

-3(x-8)-(4(-6+1/4x))=0


Domain of the equation: 4x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-3(x-8)-(4(1/4x-6))=0

We multiply parentheses

-3x-(4(1/4x-6))+24=0

We multiply all the terms by the denominator


-3x*4x+24*4x-6))-(4(1-6))=0

We add all the numbers together, and all the variables

-3x*4x+24*4x-6))-(4(-5))=0

We add all the numbers together, and all the variables

-3x*4x+24*4x=0

Wy multiply elements

-12x^2+96x=0

a = -12; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·(-12)·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*-12}=\frac{-192}{-24}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*-12}=\frac{0}{-24}
=0
$