-3(x-6)4(x1)=7x-10

Solution for -3(x-6)4(x1)=7x-10 equation:

-3(x-6)4(x1)=7x-10

We move all terms to the left:

-3(x-6)4(x1)-(7x-10)=0

We multiply parentheses

-12x^2+72x-(7x-10)=0

We get rid of parentheses

-12x^2+72x-7x+10=0

We add all the numbers together, and all the variables

-12x^2+65x+10=0

a = -12; b = 65; c = +10;
Δ = b2-4ac
Δ = 652-4·(-12)·10
Δ = 4705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{4705}}{2*-12}=\frac{-65-\sqrt{4705}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{4705}}{2*-12}=\frac{-65+\sqrt{4705}}{-24}
$