-3(x-6)+1=6(x-2)+58

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Solution for -3(x-6)+1=6(x-2)+58 equation: 



-3(x-6)+1=6(x-2)+58

We move all terms to the left:

-3(x-6)+1-(6(x-2)+58)=0

We multiply parentheses

-3x-(6(x-2)+58)+18+1=0



We calculate terms in parentheses: -(6(x-2)+58), so:

6(x-2)+58

We multiply parentheses

6x-12+58

We add all the numbers together, and all the variables

6x+46

Back to the equation:

-(6x+46)



We add all the numbers together, and all the variables

-3x-(6x+46)+19=0

We get rid of parentheses

-3x-6x-46+19=0

We add all the numbers together, and all the variables

-9x-27=0

We move all terms containing x to the left, all other terms to the right

-9x=27

x=27/-9

x=-3

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