-3(x-4)=3(-8-1/2x

Solution for -3(x-4)=3(-8-1/2x equation:

-3(x-4)=3(-8-1/2x

We move all terms to the left:

-3(x-4)-(3(-8-1/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-3(x-4)-(3(-1/2x-8)=0

We multiply parentheses

-3x-(3(-1/2x-8)+12=0

We multiply all the terms by the denominator


-3x*2x-8)+12-(3(-1=0

We add all the numbers together, and all the variables

-3x*2x=0

Wy multiply elements

-6x^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$