-3(x-4)+5x=6(x-8)+20

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Solution for -3(x-4)+5x=6(x-8)+20 equation: 



-3(x-4)+5x=6(x-8)+20

We move all terms to the left:

-3(x-4)+5x-(6(x-8)+20)=0

We add all the numbers together, and all the variables

5x-3(x-4)-(6(x-8)+20)=0

We multiply parentheses

5x-3x-(6(x-8)+20)+12=0



We calculate terms in parentheses: -(6(x-8)+20), so:

6(x-8)+20

We multiply parentheses

6x-48+20

We add all the numbers together, and all the variables

6x-28

Back to the equation:

-(6x-28)



We add all the numbers together, and all the variables

2x-(6x-28)+12=0

We get rid of parentheses

2x-6x+28+12=0

We add all the numbers together, and all the variables

-4x+40=0

We move all terms containing x to the left, all other terms to the right

-4x=-40

x=-40/-4

x=+10

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