-3(x-3)(x+3)=0

Solution for -3(x-3)(x+3)=0 equation:

Simplifying
-3(x + -3)(x + 3) = 0

Reorder the terms:
-3(-3 + x)(x + 3) = 0

Reorder the terms:
-3(-3 + x)(3 + x) = 0

Multiply (-3 + x) * (3 + x)
-3(-3(3 + x) + x(3 + x)) = 0
-3((3 * -3 + x * -3) + x(3 + x)) = 0
-3((-9 + -3x) + x(3 + x)) = 0
-3(-9 + -3x + (3 * x + x * x)) = 0
-3(-9 + -3x + (3x + x2)) = 0

Combine like terms: -3x + 3x = 0
-3(-9 + 0 + x2) = 0
-3(-9 + x2) = 0
(-9 * -3 + x2 * -3) = 0
(27 + -3x2) = 0

Solving
27 + -3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + -3x2 = 0 + -27

Combine like terms: 27 + -27 = 0
0 + -3x2 = 0 + -27
-3x2 = 0 + -27

Combine like terms: 0 + -27 = -27
-3x2 = -27

Divide each side by '-3'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}