-3(x-2)=4x+3(4-x)

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Solution for -3(x-2)=4x+3(4-x) equation: 



-3(x-2)=4x+3(4-x)

We move all terms to the left:

-3(x-2)-(4x+3(4-x))=0

We add all the numbers together, and all the variables

-3(x-2)-(4x+3(-1x+4))=0

We multiply parentheses

-3x-(4x+3(-1x+4))+6=0



We calculate terms in parentheses: -(4x+3(-1x+4)), so:

4x+3(-1x+4)

We multiply parentheses

4x-3x+12

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

-3x-x-12+6=0

We add all the numbers together, and all the variables

-4x-6=0

We move all terms containing x to the left, all other terms to the right

-4x=6

x=6/-4

x=-1+1/2

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