-3(x-2)=2(2x+1)-3

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Solution for -3(x-2)=2(2x+1)-3 equation: 



-3(x-2)=2(2x+1)-3

We move all terms to the left:

-3(x-2)-(2(2x+1)-3)=0

We multiply parentheses

-3x-(2(2x+1)-3)+6=0



We calculate terms in parentheses: -(2(2x+1)-3), so:

2(2x+1)-3

We multiply parentheses

4x+2-3

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

-3x-4x+1+6=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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