-3(x-2)+12=6+x

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Solution for -3(x-2)+12=6+x equation: 



-3(x-2)+12=6+x

We move all terms to the left:

-3(x-2)+12-(6+x)=0

We add all the numbers together, and all the variables

-3(x-2)-(x+6)+12=0

We multiply parentheses

-3x-(x+6)+6+12=0

We get rid of parentheses

-3x-x-6+6+12=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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