-3(x+4)+27=9(x-2)-15

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Solution for -3(x+4)+27=9(x-2)-15 equation: 



-3(x+4)+27=9(x-2)-15

We move all terms to the left:

-3(x+4)+27-(9(x-2)-15)=0

We multiply parentheses

-3x-(9(x-2)-15)-12+27=0



We calculate terms in parentheses: -(9(x-2)-15), so:

9(x-2)-15

We multiply parentheses

9x-18-15

We add all the numbers together, and all the variables

9x-33

Back to the equation:

-(9x-33)



We add all the numbers together, and all the variables

-3x-(9x-33)+15=0

We get rid of parentheses

-3x-9x+33+15=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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