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-3(x+1)+5x+5=19+5(2x-3)-6x
We move all terms to the left:
-3(x+1)+5x+5-(19+5(2x-3)-6x)=0
We add all the numbers together, and all the variables
5x-3(x+1)-(19+5(2x-3)-6x)+5=0
We multiply parentheses
5x-3x-(19+5(2x-3)-6x)-3+5=0
We calculate terms in parentheses: -(19+5(2x-3)-6x), so:We add all the numbers together, and all the variables
19+5(2x-3)-6x
determiningTheFunctionDomain 5(2x-3)-6x+19
We add all the numbers together, and all the variables
-6x+5(2x-3)+19
We multiply parentheses
-6x+10x-15+19
We add all the numbers together, and all the variables
4x+4
Back to the equation:
-(4x+4)
2x-(4x+4)+2=0
We get rid of parentheses
2x-4x-4+2=0
We add all the numbers together, and all the variables
-2x-2=0
We move all terms containing x to the left, all other terms to the right
-2x=2
x=2/-2
x=-1
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