-3(x+1)+5x+5=19+5(2x-3)-6

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Solution for -3(x+1)+5x+5=19+5(2x-3)-6 equation: 



-3(x+1)+5x+5=19+5(2x-3)-6

We move all terms to the left:

-3(x+1)+5x+5-(19+5(2x-3)-6)=0

We add all the numbers together, and all the variables

5x-3(x+1)-(19+5(2x-3)-6)+5=0

We multiply parentheses

5x-3x-(19+5(2x-3)-6)-3+5=0



We calculate terms in parentheses: -(19+5(2x-3)-6), so:

19+5(2x-3)-6

determiningTheFunctionDomain
5(2x-3)+19-6

We add all the numbers together, and all the variables

5(2x-3)+13

We multiply parentheses

10x-15+13

We add all the numbers together, and all the variables

10x-2

Back to the equation:

-(10x-2)



We add all the numbers together, and all the variables

2x-(10x-2)+2=0

We get rid of parentheses

2x-10x+2+2=0

We add all the numbers together, and all the variables

-8x+4=0

We move all terms containing x to the left, all other terms to the right

-8x=-4

x=-4/-8

x=1/2

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