-3(x+1)(2x-1)+2(3x+1)=3x(2-2x)-1

Solution for -3(x+1)(2x-1)+2(3x+1)=3x(2-2x)-1 equation:

-3(x+1)(2x-1)+2(3x+1)=3x(2-2x)-1

We move all terms to the left:

-3(x+1)(2x-1)+2(3x+1)-(3x(2-2x)-1)=0

We add all the numbers together, and all the variables

-3(x+1)(2x-1)+2(3x+1)-(3x(-2x+2)-1)=0

We multiply parentheses

-3(x+1)(2x-1)+6x-(3x(-2x+2)-1)+2=0

We multiply parentheses ..

-3(+2x^2-1x+2x-1)+6x-(3x(-2x+2)-1)+2=0


We calculate terms in parentheses: -(3x(-2x+2)-1), so:

3x(-2x+2)-1

We multiply parentheses

-6x^2+6x-1

Back to the equation:

-(-6x^2+6x-1)


We multiply parentheses

-6x^2-(-6x^2+6x-1)+3x-6x+6x+3+2=0

We get rid of parentheses

-6x^2+6x^2-6x+3x-6x+6x+1+3+2=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2