-3(w+2)(-w+6)=0

Solution for -3(w+2)(-w+6)=0 equation:

-3(w+2)(-w+6)=0

We add all the numbers together, and all the variables

-3(w+2)(-1w+6)=0

We multiply parentheses ..

-3(-1w^2+6w-2w+12)=0

We multiply parentheses

3w^2-18w+6w-36=0

We add all the numbers together, and all the variables

3w^2-12w-36=0

a = 3; b = -12; c = -36;
Δ = b2-4ac
Δ = -122-4·3·(-36)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*3}=\frac{-12}{6}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*3}=\frac{36}{6}
=6
$