-3(v+4)=9v-9+3(2v+4)

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Solution for -3(v+4)=9v-9+3(2v+4) equation: 



-3(v+4)=9v-9+3(2v+4)

We move all terms to the left:

-3(v+4)-(9v-9+3(2v+4))=0

We multiply parentheses

-3v-(9v-9+3(2v+4))-12=0



We calculate terms in parentheses: -(9v-9+3(2v+4)), so:

9v-9+3(2v+4)

determiningTheFunctionDomain
9v+3(2v+4)-9

We multiply parentheses

9v+6v+12-9

We add all the numbers together, and all the variables

15v+3

Back to the equation:

-(15v+3)



We get rid of parentheses

-3v-15v-3-12=0

We add all the numbers together, and all the variables

-18v-15=0

We move all terms containing v to the left, all other terms to the right

-18v=15

v=15/-18

v=-5/6

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