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-3(u+4)=3u-6+2(6u+2)
We move all terms to the left:
-3(u+4)-(3u-6+2(6u+2))=0
We multiply parentheses
-3u-(3u-6+2(6u+2))-12=0
We calculate terms in parentheses: -(3u-6+2(6u+2)), so:We get rid of parentheses
3u-6+2(6u+2)
determiningTheFunctionDomain 3u+2(6u+2)-6
We multiply parentheses
3u+12u+4-6
We add all the numbers together, and all the variables
15u-2
Back to the equation:
-(15u-2)
-3u-15u+2-12=0
We add all the numbers together, and all the variables
-18u-10=0
We move all terms containing u to the left, all other terms to the right
-18u=10
u=10/-18
u=-5/9
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