-3(u+3)=2u-6+2(5u+3)

Solution for -3(u+3)=2u-6+2(5u+3) equation:

-3(u+3)=2u-6+2(5u+3)

We move all terms to the left:

-3(u+3)-(2u-6+2(5u+3))=0

We multiply parentheses

-3u-(2u-6+2(5u+3))-9=0


We calculate terms in parentheses: -(2u-6+2(5u+3)), so:

2u-6+2(5u+3)

determiningTheFunctionDomain
2u+2(5u+3)-6

We multiply parentheses

2u+10u+6-6

We add all the numbers together, and all the variables

12u

Back to the equation:

-(12u)


We add all the numbers together, and all the variables

-15u-9=0

We move all terms containing u to the left, all other terms to the right

-15u=9

u=9/-15

u=-3/5