-3(u+1)=3u-5+2(3u+3)

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Solution for -3(u+1)=3u-5+2(3u+3) equation: 



-3(u+1)=3u-5+2(3u+3)

We move all terms to the left:

-3(u+1)-(3u-5+2(3u+3))=0

We multiply parentheses

-3u-(3u-5+2(3u+3))-3=0



We calculate terms in parentheses: -(3u-5+2(3u+3)), so:

3u-5+2(3u+3)

determiningTheFunctionDomain
3u+2(3u+3)-5

We multiply parentheses

3u+6u+6-5

We add all the numbers together, and all the variables

9u+1

Back to the equation:

-(9u+1)



We get rid of parentheses

-3u-9u-1-3=0

We add all the numbers together, and all the variables

-12u-4=0

We move all terms containing u to the left, all other terms to the right

-12u=4

u=4/-12

u=-1/3

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