-3(t-2)-(t+1)=2

Solution for -3(t-2)-(t+1)=2 equation:

Simplifying
-3(t + -2) + -1(t + 1) = 2

Reorder the terms:
-3(-2 + t) + -1(t + 1) = 2
(-2 * -3 + t * -3) + -1(t + 1) = 2
(6 + -3t) + -1(t + 1) = 2

Reorder the terms:
6 + -3t + -1(1 + t) = 2
6 + -3t + (1 * -1 + t * -1) = 2
6 + -3t + (-1 + -1t) = 2

Reorder the terms:
6 + -1 + -3t + -1t = 2

Combine like terms: 6 + -1 = 5
5 + -3t + -1t = 2

Combine like terms: -3t + -1t = -4t
5 + -4t = 2

Solving
5 + -4t = 2

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -4t = 2 + -5

Combine like terms: 5 + -5 = 0
0 + -4t = 2 + -5
-4t = 2 + -5

Combine like terms: 2 + -5 = -3
-4t = -3

Divide each side by '-4'.
t = 0.75

Simplifying
t = 0.75