-3(t-2)-(t+1)=10

Solution for -3(t-2)-(t+1)=10 equation:

Simplifying
-3(t + -2) + -1(t + 1) = 10

Reorder the terms:
-3(-2 + t) + -1(t + 1) = 10
(-2 * -3 + t * -3) + -1(t + 1) = 10
(6 + -3t) + -1(t + 1) = 10

Reorder the terms:
6 + -3t + -1(1 + t) = 10
6 + -3t + (1 * -1 + t * -1) = 10
6 + -3t + (-1 + -1t) = 10

Reorder the terms:
6 + -1 + -3t + -1t = 10

Combine like terms: 6 + -1 = 5
5 + -3t + -1t = 10

Combine like terms: -3t + -1t = -4t
5 + -4t = 10

Solving
5 + -4t = 10

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -4t = 10 + -5

Combine like terms: 5 + -5 = 0
0 + -4t = 10 + -5
-4t = 10 + -5

Combine like terms: 10 + -5 = 5
-4t = 5

Divide each side by '-4'.
t = -1.25

Simplifying
t = -1.25