-3(t+2)=8(t+1)-11(t-2)

Solution for -3(t+2)=8(t+1)-11(t-2) equation:

Simplifying
-3(t + 2) = 8(t + 1) + -11(t + -2)

Reorder the terms:
-3(2 + t) = 8(t + 1) + -11(t + -2)
(2 * -3 + t * -3) = 8(t + 1) + -11(t + -2)
(-6 + -3t) = 8(t + 1) + -11(t + -2)

Reorder the terms:
-6 + -3t = 8(1 + t) + -11(t + -2)
-6 + -3t = (1 * 8 + t * 8) + -11(t + -2)
-6 + -3t = (8 + 8t) + -11(t + -2)

Reorder the terms:
-6 + -3t = 8 + 8t + -11(-2 + t)
-6 + -3t = 8 + 8t + (-2 * -11 + t * -11)
-6 + -3t = 8 + 8t + (22 + -11t)

Reorder the terms:
-6 + -3t = 8 + 22 + 8t + -11t

Combine like terms: 8 + 22 = 30
-6 + -3t = 30 + 8t + -11t

Combine like terms: 8t + -11t = -3t
-6 + -3t = 30 + -3t

Add '3t' to each side of the equation.
-6 + -3t + 3t = 30 + -3t + 3t

Combine like terms: -3t + 3t = 0
-6 + 0 = 30 + -3t + 3t
-6 = 30 + -3t + 3t

Combine like terms: -3t + 3t = 0
-6 = 30 + 0
-6 = 30

Solving
-6 = 30

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.