-3(t+12)+10=-8

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Solution for -3(t+12)+10=-8 equation: 



-3(t+12)+10=-8

We move all terms to the left:

-3(t+12)+10-(-8)=0

We add all the numbers together, and all the variables

-3(t+12)+18=0

We multiply parentheses

-3t-36+18=0

We add all the numbers together, and all the variables

-3t-18=0

We move all terms containing t to the left, all other terms to the right

-3t=18

t=18/-3

t=-6

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