-3(r+4)=-7r+2(-7+r)

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Solution for -3(r+4)=-7r+2(-7+r) equation: 



-3(r+4)=-7r+2(-7+r)

We move all terms to the left:

-3(r+4)-(-7r+2(-7+r))=0

We add all the numbers together, and all the variables

-3(r+4)-(-7r+2(r-7))=0

We multiply parentheses

-3r-(-7r+2(r-7))-12=0



We calculate terms in parentheses: -(-7r+2(r-7)), so:

-7r+2(r-7)

We multiply parentheses

-7r+2r-14

We add all the numbers together, and all the variables

-5r-14

Back to the equation:

-(-5r-14)



We get rid of parentheses

-3r+5r+14-12=0

We add all the numbers together, and all the variables

2r+2=0

We move all terms containing r to the left, all other terms to the right

2r=-2

r=-2/2

r=-1

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