-3(n-5)-(4n-1)=-6+(3n-1)

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Solution for -3(n-5)-(4n-1)=-6+(3n-1) equation: 



-3(n-5)-(4n-1)=-6+(3n-1)

We move all terms to the left:

-3(n-5)-(4n-1)-(-6+(3n-1))=0

We multiply parentheses

-3n-(4n-1)-(-6+(3n-1))+15=0

We get rid of parentheses

-3n-4n-(-6+(3n-1))+1+15=0



We calculate terms in parentheses: -(-6+(3n-1)), so:

-6+(3n-1)

determiningTheFunctionDomain
(3n-1)-6

We get rid of parentheses

3n-1-6

We add all the numbers together, and all the variables

3n-7

Back to the equation:

-(3n-7)



We add all the numbers together, and all the variables

-7n-(3n-7)+16=0

We get rid of parentheses

-7n-3n+7+16=0

We add all the numbers together, and all the variables

-10n+23=0

We move all terms containing n to the left, all other terms to the right

-10n=-23

n=-23/-10

n=2+3/10

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