-3(n-5)-(4n-1)=-5+(2n-1)

Solution for -3(n-5)-(4n-1)=-5+(2n-1) equation:

-3(n-5)-(4n-1)=-5+(2n-1)

We move all terms to the left:

-3(n-5)-(4n-1)-(-5+(2n-1))=0

We multiply parentheses

-3n-(4n-1)-(-5+(2n-1))+15=0

We get rid of parentheses

-3n-4n-(-5+(2n-1))+1+15=0


We calculate terms in parentheses: -(-5+(2n-1)), so:

-5+(2n-1)

determiningTheFunctionDomain
(2n-1)-5

We get rid of parentheses

2n-1-5

We add all the numbers together, and all the variables

2n-6

Back to the equation:

-(2n-6)


We add all the numbers together, and all the variables

-7n-(2n-6)+16=0

We get rid of parentheses

-7n-2n+6+16=0

We add all the numbers together, and all the variables

-9n+22=0

We move all terms containing n to the left, all other terms to the right

-9n=-22

n=-22/-9

n=2+4/9