-3(n+2)-8n=-7(n+3)-n

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Solution for -3(n+2)-8n=-7(n+3)-n equation:



-3(n+2)-8n=-7(n+3)-n
We move all terms to the left:
-3(n+2)-8n-(-7(n+3)-n)=0
We add all the numbers together, and all the variables
-8n-3(n+2)-(-7(n+3)-n)=0
We multiply parentheses
-8n-3n-(-7(n+3)-n)-6=0
We calculate terms in parentheses: -(-7(n+3)-n), so:
-7(n+3)-n
We add all the numbers together, and all the variables
-1n-7(n+3)
We multiply parentheses
-1n-7n-21
We add all the numbers together, and all the variables
-8n-21
Back to the equation:
-(-8n-21)
We add all the numbers together, and all the variables
-11n-(-8n-21)-6=0
We get rid of parentheses
-11n+8n+21-6=0
We add all the numbers together, and all the variables
-3n+15=0
We move all terms containing n to the left, all other terms to the right
-3n=-15
n=-15/-3
n=+5

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