-3(n+-18)=96

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Solution for -3(n+-18)=96 equation: 



-3(n+-18)=96

We move all terms to the left:

-3(n+-18)-(96)=0

We add all the numbers together, and all the variables

-3(n-18)-96=0

We multiply parentheses

-3n+54-96=0

We add all the numbers together, and all the variables

-3n-42=0

We move all terms containing n to the left, all other terms to the right

-3n=42

n=42/-3

n=-14

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