-3(m-2)+4m-8=10

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Solution for -3(m-2)+4m-8=10 equation: 



-3(m-2)+4m-8=10

We move all terms to the left:

-3(m-2)+4m-8-(10)=0

We add all the numbers together, and all the variables

4m-3(m-2)-18=0

We multiply parentheses

4m-3m+6-18=0

We add all the numbers together, and all the variables

m-12=0

We move all terms containing m to the left, all other terms to the right

m=12

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