-3(k-5)=3(1-3k)

Solution for -3(k-5)=3(1-3k) equation:

-3(k-5)=3(1-3k)

We move all terms to the left:

-3(k-5)-(3(1-3k))=0

We add all the numbers together, and all the variables

-3(k-5)-(3(-3k+1))=0

We multiply parentheses

-3k-(3(-3k+1))+15=0


We calculate terms in parentheses: -(3(-3k+1)), so:

3(-3k+1)

We multiply parentheses

-9k+3

Back to the equation:

-(-9k+3)


We get rid of parentheses

-3k+9k-3+15=0

We add all the numbers together, and all the variables

6k+12=0

We move all terms containing k to the left, all other terms to the right

6k=-12

k=-12/6

k=-2