-3(k-2)=-1-4(k+)

Solution for -3(k-2)=-1-4(k+) equation:

-3(k-2)=-1-4(k+)

We move all terms to the left:

-3(k-2)-(-1-4(k+))=0

We add all the numbers together, and all the variables

-3(k-2)-(-1-4(+k))=0

We multiply parentheses

-3k-(-1-4(+k))+6=0


We calculate terms in parentheses: -(-1-4(+k)), so:

-1-4(+k)

determiningTheFunctionDomain
-4(+k)-1

We multiply parentheses

-4k-1

Back to the equation:

-(-4k-1)


We get rid of parentheses

-3k+4k+1+6=0

We add all the numbers together, and all the variables

k+7=0

We move all terms containing k to the left, all other terms to the right

k=-7