-3(j+8)+-12=3

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Solution for -3(j+8)+-12=3 equation: 



-3(j+8)+-12=3

We move all terms to the left:

-3(j+8)+-12-(3)=0

determiningTheFunctionDomain
-3(j+8)-12-3+=0

We add all the numbers together, and all the variables

-3(j+8)=0

We multiply parentheses

-3j-24=0

We move all terms containing j to the left, all other terms to the right

-3j=24

j=24/-3

j=-8

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