-3(j+-2)=18

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Solution for -3(j+-2)=18 equation: 



-3(j+-2)=18

We move all terms to the left:

-3(j+-2)-(18)=0

We add all the numbers together, and all the variables

-3(j-2)-18=0

We multiply parentheses

-3j+6-18=0

We add all the numbers together, and all the variables

-3j-12=0

We move all terms containing j to the left, all other terms to the right

-3j=12

j=12/-3

j=-4

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