-3(d-4)=-4(d+3)+d+24

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Solution for -3(d-4)=-4(d+3)+d+24 equation: 



-3(d-4)=-4(d+3)+d+24

We move all terms to the left:

-3(d-4)-(-4(d+3)+d+24)=0

We multiply parentheses

-3d-(-4(d+3)+d+24)+12=0



We calculate terms in parentheses: -(-4(d+3)+d+24), so:

-4(d+3)+d+24

We add all the numbers together, and all the variables

d-4(d+3)+24

We multiply parentheses

d-4d-12+24

We add all the numbers together, and all the variables

-3d+12

Back to the equation:

-(-3d+12)



We get rid of parentheses

-3d+3d-12+12=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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