-3(d+2)-d-5=-4(d+4)+5

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Solution for -3(d+2)-d-5=-4(d+4)+5 equation: 



-3(d+2)-d-5=-4(d+4)+5

We move all terms to the left:

-3(d+2)-d-5-(-4(d+4)+5)=0

We add all the numbers together, and all the variables

-1d-3(d+2)-(-4(d+4)+5)-5=0

We multiply parentheses

-1d-3d-(-4(d+4)+5)-6-5=0



We calculate terms in parentheses: -(-4(d+4)+5), so:

-4(d+4)+5

We multiply parentheses

-4d-16+5

We add all the numbers together, and all the variables

-4d-11

Back to the equation:

-(-4d-11)



We add all the numbers together, and all the variables

-4d-(-4d-11)-11=0

We get rid of parentheses

-4d+4d+11-11=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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