-3(c-4)-2c-8=9(c+)+1

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Solution for -3(c-4)-2c-8=9(c+)+1 equation: 



-3(c-4)-2c-8=9(c+)+1

We move all terms to the left:

-3(c-4)-2c-8-(9(c+)+1)=0

We add all the numbers together, and all the variables

-3(c-4)-2c-(9(+c)+1)-8=0

We add all the numbers together, and all the variables

-2c-3(c-4)-(9(+c)+1)-8=0

We multiply parentheses

-2c-3c-(9(+c)+1)+12-8=0



We calculate terms in parentheses: -(9(+c)+1), so:

9(+c)+1

We multiply parentheses

9c+1

Back to the equation:

-(9c+1)



We add all the numbers together, and all the variables

-5c-(9c+1)+4=0

We get rid of parentheses

-5c-9c-1+4=0

We add all the numbers together, and all the variables

-14c+3=0

We move all terms containing c to the left, all other terms to the right

-14c=-3

c=-3/-14

c=3/14

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