-3(c-4)+8c=4(c-2)

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Solution for -3(c-4)+8c=4(c-2) equation: 



-3(c-4)+8c=4(c-2)

We move all terms to the left:

-3(c-4)+8c-(4(c-2))=0

We add all the numbers together, and all the variables

8c-3(c-4)-(4(c-2))=0

We multiply parentheses

8c-3c-(4(c-2))+12=0



We calculate terms in parentheses: -(4(c-2)), so:

4(c-2)

We multiply parentheses

4c-8

Back to the equation:

-(4c-8)



We add all the numbers together, and all the variables

5c-(4c-8)+12=0

We get rid of parentheses

5c-4c+8+12=0

We add all the numbers together, and all the variables

c+20=0

We move all terms containing c to the left, all other terms to the right

c=-20

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