-3(b-8)-8=-9(b+2)+4

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Solution for -3(b-8)-8=-9(b+2)+4 equation: 



-3(b-8)-8=-9(b+2)+4

We move all terms to the left:

-3(b-8)-8-(-9(b+2)+4)=0

We multiply parentheses

-3b-(-9(b+2)+4)+24-8=0



We calculate terms in parentheses: -(-9(b+2)+4), so:

-9(b+2)+4

We multiply parentheses

-9b-18+4

We add all the numbers together, and all the variables

-9b-14

Back to the equation:

-(-9b-14)



We add all the numbers together, and all the variables

-3b-(-9b-14)+16=0

We get rid of parentheses

-3b+9b+14+16=0

We add all the numbers together, and all the variables

6b+30=0

We move all terms containing b to the left, all other terms to the right

6b=-30

b=-30/6

b=-5

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