-3(b-10)=12

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Solution for -3(b-10)=12 equation: 



-3(b-10)=12

We move all terms to the left:

-3(b-10)-(12)=0

We multiply parentheses

-3b+30-12=0

We add all the numbers together, and all the variables

-3b+18=0

We move all terms containing b to the left, all other terms to the right

-3b=-18

b=-18/-3

b=+6

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