-3(b+8)=3(b-1)

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Solution for -3(b+8)=3(b-1) equation: 



-3(b+8)=3(b-1)

We move all terms to the left:

-3(b+8)-(3(b-1))=0

We multiply parentheses

-3b-(3(b-1))-24=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

-3b-3b+3-24=0

We add all the numbers together, and all the variables

-6b-21=0

We move all terms containing b to the left, all other terms to the right

-6b=21

b=21/-6

b=-3+1/2

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