-3(b+12)=3

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Solution for -3(b+12)=3 equation: 



-3(b+12)=3

We move all terms to the left:

-3(b+12)-(3)=0

We multiply parentheses

-3b-36-3=0

We add all the numbers together, and all the variables

-3b-39=0

We move all terms containing b to the left, all other terms to the right

-3b=39

b=39/-3

b=-13

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