-3(b+1)=1-(4b-1)

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Solution for -3(b+1)=1-(4b-1) equation: 



-3(b+1)=1-(4b-1)

We move all terms to the left:

-3(b+1)-(1-(4b-1))=0

We multiply parentheses

-3b-(1-(4b-1))-3=0



We calculate terms in parentheses: -(1-(4b-1)), so:

1-(4b-1)

determiningTheFunctionDomain
-(4b-1)+1

We get rid of parentheses

-4b+1+1

We add all the numbers together, and all the variables

-4b+2

Back to the equation:

-(-4b+2)



We get rid of parentheses

-3b+4b-2-3=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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