-3(8-a)-4a=6a-2(a+2)a=

Solution for -3(8-a)-4a=6a-2(a+2)a= equation:

-3(8-a)-4a=6a-2(a+2)a=

We move all terms to the left:

-3(8-a)-4a-(6a-2(a+2)a)=0

We add all the numbers together, and all the variables

-3(-1a+8)-4a-(6a-2(a+2)a)=0

We add all the numbers together, and all the variables

-4a-3(-1a+8)-(6a-2(a+2)a)=0

We multiply parentheses

-4a+3a-(6a-2(a+2)a)-24=0


We calculate terms in parentheses: -(6a-2(a+2)a), so:

6a-2(a+2)a

We multiply parentheses

-2a^2+6a-4a

We add all the numbers together, and all the variables

-2a^2+2a

Back to the equation:

-(-2a^2+2a)


We add all the numbers together, and all the variables

-(-2a^2+2a)-1a-24=0

We get rid of parentheses

2a^2-2a-1a-24=0

We add all the numbers together, and all the variables

2a^2-3a-24=0

a = 2; b = -3; c = -24;
Δ = b2-4ac
Δ = -32-4·2·(-24)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{201}}{2*2}=\frac{3-\sqrt{201}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{201}}{2*2}=\frac{3+\sqrt{201}}{4}
$