-3(8+4x)-2(x-3)=10-(x+8)

Solution for -3(8+4x)-2(x-3)=10-(x+8) equation:

-3(8+4x)-2(x-3)=10-(x+8)

We move all terms to the left:

-3(8+4x)-2(x-3)-(10-(x+8))=0

We add all the numbers together, and all the variables

-3(4x+8)-2(x-3)-(10-(x+8))=0

We multiply parentheses

-12x-2x-(10-(x+8))-24+6=0


We calculate terms in parentheses: -(10-(x+8)), so:

10-(x+8)

determiningTheFunctionDomain
-(x+8)+10

We get rid of parentheses

-x-8+10

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)


We add all the numbers together, and all the variables

-14x-(-1x+2)-18=0

We get rid of parentheses

-14x+1x-2-18=0

We add all the numbers together, and all the variables

-13x-20=0

We move all terms containing x to the left, all other terms to the right

-13x=20

x=20/-13

x=-1+7/13